45p^2+24p-36=0

Solution for 45p^2+24p-36=0 equation:

45p^2+24p-36=0

a = 45; b = 24; c = -36;
Δ = b2-4ac
Δ = 242-4·45·(-36)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-84}{2*45}=\frac{-108}{90}
=-1+1/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+84}{2*45}=\frac{60}{90}
=2/3
$